Extract filaname from path with regex

Extracting filname from the full path when the path is OPTIONAL is not so easy as it looks at first look.
I would like to extract cc.cc from
/aa/bb/cc.cc 
either from
cc.cc
as well.

Solution:

$ echo "/aa/bb/cc.cc" | perl -pe "s|(?:.*/)?([^/]*)|\1|"
cc.cc
$ echo "/aa/cc.cc" | perl -pe "s|(?:.*/)?([^/]*)|\1|"
cc.cc
$ echo "cc.cc" | perl -pe "s|(?:.*/)?([^/]*)|\1|"
cc.cc

Some explanation: 

• ?: start non capturing group
• [^/] any character except slash